Google Dynamic Links for Firebase

To use this plugin, add firebase_dynamic_links as a dependency in your pubspec.yaml file. You must also configure firebase dynamic links for each platform project: Android and iOS (see the example folder for details).

You create a Dynamic Link either by using the Firebase console, using a REST API, iOS or Android Builder API, Flutter API, or by forming a URL by adding Dynamic Link parameters to a URI prefix specific to your app. These parameters specify the links you want to open, depending on the user's platform and whether your app is installed.

Below are instructions to create Dynamic Links using Flutter with the Firebase Dynamic Links API. This API accepts either a long Dynamic Link or an object containing Dynamic Link parameters, and returns a URL like the following example:

https://example.page.link/WXYZ

You can create a Dynamic Link programmatically by setting the following parameters and using the DynamicLinkParameters.buildUrl() method.

final DynamicLinkParameters parameters = DynamicLinkParameters(
  uriPrefix: 'https://abc123.app.goo.gl',
  link: Uri.parse('https://example.com/'),
  androidParameters: AndroidParameters(
      packageName: 'com.example.android',
      minimumVersion: 125,
  ),
  iosParameters: IosParameters(
      bundleId: 'com.example.ios',
      minimumVersion: '1.0.1',
      appStoreId: '123456789',
  ),
  googleAnalyticsParameters: GoogleAnalyticsParameters(
      campaign: 'example-promo',
      medium: 'social',
      source: 'orkut',
  ),
  itunesConnectAnalyticsParameters: ItunesConnectAnalyticsParameters(
    providerToken: '123456',
    campaignToken: 'example-promo',
  ),
  socialMetaTagParameters:  SocialMetaTagParameters(
    title: 'Example of a Dynamic Link',
    description: 'This link works whether app is installed or not!',
  ),
);

final Uri dynamicUrl = await parameters.buildUrl();

To create a short Dynamic Link, build DynamicLinkParameters the same way, but use the DynamicLinkParameters.buildShortLink() method.

final ShortDynamicLink shortDynamicLink = await parameters.buildShortLink();
final Uri shortUrl = shortDynamicLink.shortUrl;

To shorten a long Dynamic Link, use the DynamicLinkParameters.shortenUrl method.

final ShortDynamicLink shortenedLink = await DynamicLinkParameters.shortenUrl(
  Uri.parse('https://example.page.link/?link=https://example.com/&apn=com.example.android&ibn=com.example.ios'),
  DynamicLinkParametersOptions(ShortDynamicLinkPathLength.unguessable),
);

final Uri shortUrl = shortenedLink.shortUrl;

You can receive a Dynamic Link containing a deep link that takes the user to specific content within your app:

1. In the Firebase Console, open the Dynamic Links section.
   • Accept the terms of service if you are prompted to do so.
   • Take note of your project's Dynamic Links URL prefix, which is displayed at the top of the Dynamic Links page. You need your project's Dynamic Links URL prefix to programmatically create Dynamic Links. Unless you are using a custom domain, a Dynamic Links URL prefix looks like https://YOUR_SUBDOMAIN.page.link.

Receiving dynamic links on iOS requires a couple more steps than Android. If you only want to receive dynamic links on Android, skip to step 5. You can also follow a video on the next two steps here.

2. In the Info tab of your iOS app's Xcode project:

   • Create a new URL Type to be used for Dynamic Links.
   • Set the Identifier field to a unique value and the URL Schemes field to be your bundle identifier, which is the default URL scheme used by Dynamic Links.

3. In the Capabilities tab of your app's Xcode project, enable Associated Domains and add the following to the Associated Domains list:

applinks:YOUR_URL_PREFIX

Remember not to include https:// or any slashes or paths in your prefix

4. If you are using a custom domain create an key in your Info.plist file called FirebaseDynamicLinksCustomDomains and set it to your app's Dynamic Link URL prefixes. For example:

<key>FirebaseDynamicLinksCustomDomains</key>
<array>
  <string>https://example.com/promos</string>
  <string>https://example.com/links/share</string>
</array>

5. If you want to open android app directly without redirecting to Chrome or Any other Browser you can put an intent-filter in your AndroidManifest.xml file. It will open the system dialogue to open link with your app or other browsers. Users can then directly choose to open the link in your app.

Note: This step is optional and in case we do not implement this then link will open in chrome at first and then will eventually open your application.

<intent-filter>
  <action android:name="android.intent.action.VIEW" />
  <category android:name="android.intent.category.DEFAULT" />
  <category android:name="android.intent.category.BROWSABLE" />
  <!-- Accepts URIs that begin with YOUR_SCHEME://YOUR_HOST -->
  <data
    android:scheme="https"
    android:host="YOUR_SUBDOMAIN.page.link" />
</intent-filter>

6. To receive a dynamic link, call the getInitialLink() method from FirebaseDynamicLinks which gets the link that opened the app (or null if it was not opened via a dynamic link) and configure listeners for link callbacks when the application is active or in background calling onLink.

void main() {
  runApp(MaterialApp(
    title: 'Dynamic Links Example',
    routes: <String, WidgetBuilder>{
      '/': (BuildContext context) => MyHomeWidget(), // Default home route
      '/helloworld': (BuildContext context) => MyHelloWorldWidget(),
    },
  ));
}

class MyHomeWidgetState extends State<MyHomeWidget> {
  .
  .
  .
  @override
  void initState() {
    super.initState();
    this.initDynamicLinks();
  }

  void initDynamicLinks() async {
    FirebaseDynamicLinks.instance.onLink(
      onSuccess: (PendingDynamicLinkData dynamicLink) async {
        final Uri deepLink = dynamicLink?.link;

        if (deepLink != null) {
          Navigator.pushNamed(context, deepLink.path);
        }
      },
      onError: (OnLinkErrorException e) async {
        print('onLinkError');
        print(e.message);
      }
    );

    final PendingDynamicLinkData data = await FirebaseDynamicLinks.instance.getInitialLink();
    final Uri deepLink = data?.link;

    if (deepLink != null) {
      Navigator.pushNamed(context, deepLink.path);
    }
  }
  .
  .
  .
}

If your app did not open from a dynamic link, getInitialLink() will return null.

See the example directory for a complete sample app using Google Dynamic Links for Firebase.

Please file FlutterFire specific issues, bugs, or feature requests in our issue tracker.

Plugin issues that are not specific to Flutterfire can be filed in the Flutter issue tracker.

To contribute a change to this plugin, please review our contribution guide and open a pull request.